SHM and uniform circular motion

Consider a particle moving on a circle of radius A with a constant angular speed ω as shown in figure.

Suppose the particle is at point Po on the circle, at t = 0. The radius OP make an angle θ = (ωt + φ) with the X-axis at time t. Drop a perpendicular PM on X-axis and drop a perpendicular PN on Y-axis. Let us trace the path followed by the points M and N with time, as particle P moves with constant angular speed on the circular path. We find, both the points M and N makes oscillatory motion, about the mean position at the center of the circle.  

 

For point ‘N’: 

Displacement of the point N from mean position is ON = Y , 

In ΔOPN  

Or     

Or       ……….. (i)

Differentiating equation (i), we get



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