{"id":5127,"date":"2022-04-06T12:40:14","date_gmt":"2022-04-06T12:40:14","guid":{"rendered":"https:\/\/physics.educour.in\/isc-physics\/?p=5127"},"modified":"2022-04-07T07:35:11","modified_gmt":"2022-04-07T07:35:11","slug":"electric-field","status":"publish","type":"post","link":"https:\/\/physics.educour.in\/isc-physics\/electric-field\/","title":{"rendered":"Electric Field"},"content":{"rendered":"\t\t
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Electric field<\/span><\/h1>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 The region or space around a given charge in which some other charge experience an electrostatic force on it , is called the electric field of the (given) charge.<\/span>
\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Theoretically, the electric field of a given charge is extended upto infinity.<\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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The Intensity of Electric Field (Measure of Electric Field)<\/span><\/h3>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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\u201cThe intensity of electric field at a point is equal to the electrostatic force experienced by unit positive charge placed at that point\u201d.<\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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Electric field (intensity) is a vector quantity and it is directed along the direction of the force experienced by the positive test charge at that point. <\/span>
Electric field due to a positive charge is always away from the charge and that due to a negative charge is always towards the charges. <\/span>
Unit of [E] : newton\/coulomb = volt\/metre <\/strong><\/span>
Dimensions of [E] : = [MLT\u20133<\/sup> A\u20131<\/sup> ]<\/strong><\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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Question 1.<\/strong><\/span> A positively charged ball hangs from a long silk thread. We wish to measure E at a point in the same horizontal plane as that of the hanging charge. To do so, we put a positive test charge q0<\/sub> at the point and measure F\/q0<\/sub>. Will F\/q0<\/sub> be less than, equal to, or greater than E at the point in question?<\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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Solution<\/span>.<\/strong> <\/span>
When we try to measure the electric field at point P then, after placing the test charge at P, it repels the source charge (suspended charge) and the measured value of electric field Emeasured<\/sub> = F\/qo<\/sub> = will be less than the actual value Electric field E.<\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t

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Electric Field Due to A Point Charge:<\/span><\/h3>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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Electric Field intensity at point \u2018P\u2019, at distance r from a point charge \u2018q\u2019 is<\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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\"\"<\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\t\t

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Electric Field (basic Concept)<\/span><\/strong><\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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